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31 October, 17:14

If the factors of a quadratic function are (x + 2) and (x-9), what are the x-intercepts of the function?

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  1. 31 October, 20:50
    0
    -2 and 9 are the x-intercepts of the function.

    Step-by-step explanation:

    A polynomial contains a variable (x) raised to a power (known as a degree) and various terms or constants. Factoring a polynomial means breaking the expression down into a smaller one with terms that multiply each other.

    A quadratic function is a second-degree polynomial of the form ax²+bx+c = 0.

    The highest degree of a polynomial indicates the number of roots the polynomial has. The roots of a polynomial (also called zeros of a polynomial) are the values for which, the numerical value of the polynomial is equal to zero (where P (x) is the polynomial and "a" is the root, then P (a) = 0).

    Graphically, the roots are observed as the intersections of the graph of the polynomial with the X axis (abscissa).

    The quadratic functions, being of degree 2, admit up to a maximum of 2 real roots. However, there are cases in which only one is obtained and even others in which there is no real root.

    As mentioned, factoring the polynomial produces two smaller expressions that are multiplied to produce the original polynomial. In this case:

    (x+2) * (x-9) = 0

    This is a product of two expressions, and is equal to zero. When one or both of these expressions is zero, then the product will also be zero.

    Then x+2=0 ⇒ x=-2

    x-9=0 ⇒ x=9

    This indicates that the roots are - 2 and 9, which are the x-intercepts of the function.
  2. 31 October, 21:04
    0
    X=-2,9

    Step-by-step explanation:

    X+2=0 X=-2

    X-9=0 X=9
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