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16 July, 20:56

On the graph of f (x) = sin x and the interval (-2pi, 0), for what value of x does f (x) achieve a minimum? Choose all

answers that apply.

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  1. 16 July, 23:48
    0
    x = - pi/2

    Step-by-step explanation:

    hello:

    f (x) = sin x x⋲ (-2pi, 0)

    the derivate for f is : f' (x) = cosx

    f (x) achieve a minimum when : f' (x) = 0

    cosx = 0 genral solution is:

    x = pi/2 + kpi ... k in Z

    but : x⋲ (-2pi, 0) so : x = - pi/2 ... (k = - 1)
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