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1 May, 22:22

Linda will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $47.96 and costs an additional $0.16 per mile driven. The second plan has an initial fee of $55.96 and costs an additional $0.12 per mile driven. How many miles would Linda need to drive for the two plans to cost the same?

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  1. 2 May, 00:01
    0
    Answer: it would take 200 miles before the two plans cost the same.

    Step-by-step explanation:

    Let x represent the number of miles that Linda drives with either the first plan or the second plan.

    Let y represent the total number of miles that she drives with the first plan

    Let z represent the total number of miles that she drives with the second plan.

    The first plan has an initial fee of $47.96 and costs an additional $0.16 per mile driven. This means that the total amount for x miles would be

    y = 0.16x + 47.96

    The second plan has an initial fee of $55.96 and costs an additional $0.12 per mile driven. This means that the total amount for x hours would be

    z = 0.12x + 55.96

    To determine the number of miles before the amount for both plans becomes the same, we would equate y to z. It becomes

    0.16x + 47.96 = 0.12x + 55.96

    0.16x - 0.12x = 55.96 - 47.96

    0.04x = 8

    x = 8/0.04 = 200
  2. 2 May, 01:47
    0
    The two plans are not at the same cost

    Step-by-step explanation:

    The first plan

    47.96:0.16

    =299.75

    the secand plan

    55.96:0.12

    =466.33
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