The table represents the height of a rock that is dropped, h (t), in meters, after t seconds.

A 2-column table with 5 rows. The first column is labeled t with entries 0, 0.5, 1, 1.5, 2, 2.5, 3. The second column is labeled h (t) with entries 20, 18.8, 15.1, 9, 0.4, negative 10.6, negative 24.1.

When does the rock hit the ground?

The rock hits the ground between

seconds and

seconds after it is dropped.

The rock hits the ground between 2

seconds and 2.5

seconds after it is dropped.

Step-by-step explanation:

At 2 seconds, the height of the rock is 0.4 meters, and at 2.5 seconds the height of the rock is - 10.6 meters. Therefore, the rock hit the ground, or 0 meters, between those times.

The rock hits the ground between 2 and 2.5 seconds.

Step-by-step explanation:

The given table is:

t h (t)

0 20

0.5 18.8

1 15.1

1.5 9

2 0.4

2.5 - 10.6

3 - 24.1

The ground level is when h (t) = 0, which is between 0.4 and - 10.6, because in that interval is included the zero. So, the problem is asking when does the rock hit the ground, referring to time. We just have to look for t-values for 0.4 and - 10.6.

Therefore, the rock hits the ground between 2 and 2.5 seconds.