Jeff has some coins so he can put in 6 bags or 9 bags with no coins left but if put in 5 bags 2 coins left. So at least how many coins Jeff should have

72

Step-by-step explanation:

Jeff can divide the coin evenly in 6 or 9 bags, so the number of coin should have 9 and 6 as the factor. The lowest common factor for 6 and 9 will be:

6 = 2 x 3

9 = 3^2

LCF = 2 x 3^2 = 18

From here you need to find the common multiple of 18 that will have 2 remainder after divided by 5. When 18 (divided by 5, it will left 3 as remainder.

Multiple of 3 that give 2 remainder after divided by 5 will be 3x4 = 12. Then least coin Jeff should have will be: 4x18 = 72