what mass of water at 15 degrees celcius can be cooled 1 degree celcius by heat necessary to melt 185 grams of ice at 0 degrees celcius?

1052.944 g

Step-by-step explanation:

Given:

Initial temperature of water = 15° C

Final temperature of water = 1° C

Mass of ice = 185 grams

Now,

Heat of fusion of ice = 333.55 J/g

Thus,

The heat required to melt ice = Mass of ice * Heat of fusion

or

The heat required to melt ice = 185 * 333.55 = 61706.75 J

Now,

for water the specific heat capacity = 4.186 J/g.°C

Heat provided = mass * specific heat capacity * Change in temperature

or

61706.75 = mass * 4.186 * (15 - 1)

or

61706.75 = mass * 58.604

or

mass = 1052.944 g

Hence, the mass that can be heated 1052.944 g