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18 July, 02:19

Find a formula for the general term of each of the following sequences a) 7,13,19,25,31

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Answers (2)
  1. 18 July, 03:31
    0
    aₙ = 6n+1

    Step-by-step explanation:

    7,13,19,25,31

    Given, AP with the first term of 7, and common difference of 6

    Nth term:

    aₙ = a₁ + (n-1) d = 7 + (n-1) * 6 = 7+6n-6 = 6n+1 aₙ = 6n+1
  2. 18 July, 05:12
    0
    7+6=13

    13+6=19

    19+6=25

    25+6=31
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