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29 January, 12:25

YP=+8+10+12 + ... + 106 and Q=2+4+6+8 + ... 104 are sums of arithmetic sequences, determine which is greater, Por Q, and by how much

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  1. 29 January, 13:55
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    P is greater by 94.

    Step-by-step explanation:

    P = 8 + 10 + 12 + ... + 102 + 104 + 106

    Q = 2 + 4 + 6 + 8 + 10 + 12 + ... + 102 + 104

    The terms from 8 + 10 + ... + 104 are the same on both P and Q.

    Therefore, the different terms are the 106 in P and the 2 + 4 + 6 in Q.

    Clearly 106 > 2 + 4 + 6, so P is greater.

    To know by how much we would subtract 2 + 4 + 6 = 12 from 106.

    106 - 12 = 94.
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