Ask Question
14 November, 14:28

if - 5 is a root of the quadratic equation 2x2+px-15=0 and the quadratic equation p (x^2+x) + k=0 has equal roots. find the value of k

+1
Answers (1)
  1. 14 November, 17:41
    0
    k = 1.75

    Step-by-step explanation:

    Given that x = - 5 is a root of the equation, then this value makes the equation true. Substitute x = - 5 into the equation and solve for p

    2 ( - 5) ² + p ( - 5) - 15 = 0

    50 - 5p - 15 = 0

    - 5p + 35 = 0 (subtract 35 from both sides)

    - 5p = - 35 (divide both sides by - 5)

    p = 7

    Thus

    7 (x² + x) + k = 0, that is

    7x² + 7x + k = 0 ← in standard form

    Using the discriminant Δ = b² - 4ac to find k

    For equal roots then b² - 4ac = 0

    with a = 7, b = 7 and c = k, then

    7² - (4 * 7 * k) = 0

    49 - 28k = 0 (subtract 49 from both sides)

    - 28k = - 49 (divide both sides by - 28)

    k = 1.75
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “if - 5 is a root of the quadratic equation 2x2+px-15=0 and the quadratic equation p (x^2+x) + k=0 has equal roots. find the value of k ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers