Meg has $4 more than loc. Pat has twice as much as meg and loc combined. Let d = loc's nomber of dollars then when is mega and pats number of dollars

Meg has (4 + d) dollars

Pat has (2m + 2d) dollars

Step-by-step explanation:

Let d represents Loc's money

Let m represents Meg's money

Let p represents Pat's money

We are given that Meg has $4 more than loc

Mathematically,

m = 4 + d

Therefore, Meg has (4 + d) dollars

We are also given that Pat has twice as much as meg and loc combined

Mathematically,

p = 2 * (m + d)

p = 2m + 2d

Therefore, Pat has (2m + 2d) dollars

Note: We have 2 equations and 3 unknowns therefore, we cannot have a unique solution to this problem.