Carol sold 40 tickets to a school play for a total of $245. If each adult ticket sold for $8 and each child's ticket sold for $3,

how many of each kind did she sell?

Carol sold 15 child tickets and 25 adult tickets.

Step-by-step explanation:

Let's make a system, first let's set x to the number of child tickets sold and y to the number of adult tickets sold. We know that she sold 40 tickets in total to we have: x+y=40. Then, we know that adult tickets are sold for $8 and child tickets are sold for $3. So we have 3x+8y=245. We can solve this using substitution. If we subtract y from both sides of the first equation, we have x=-y+40. We can substitute this into the second equation:

3 (-y+40) + 8y=245

-3y+120+8y=245

5y+120=245

5y=125

y=25

Now we substitute this into any equation in the system to get the x value.

x+y=40

x+25=40

x=15

Carol sold 15 child tickets and 25 adult tickets.