Solve 5x^2-4x-2=0 by completing the square

Hello

Here's the answer:

2x^2 + 5x + 2 = 0/ / 2x^2+4x+x+2=0/ / 2x (x+2) + 1 (x+2) = 0/ / (2x+1) (x+2) = 0/ / x=-/frac{1}{2} / vee x=-2

x^2-4x+1=0/ / x^2-4x+4-3=0/ / (x-2) ^2=3/ / x-2 = / sqrt3 / vee x-2=-/sqrt3/ / x=2+/sqrt3 / vee x=2-/sqrt3