The equation of the circle whose center is at (2, 1) and radius is 3 is

A. (x + 2) ² + (y + 1) ² = 9

B. (x - 2) ² + (y - 1) ² = 9

C. (x - 2) ² + (y - 1) ² = 3

The answer is B. (x - 2) ^2 + (y - 1) ^2 = 9 I got this question right on my assignment.

B. (x - 2) ^2 + (y - 1) ^2 = 9.

Step-by-step explanation:

The general equation for a circle can be written as:

(x - a) ^2 + (y - b) ^2 = r^2 where the centre is at (a, b) and the radius = r.

Here a = 2, b = 1 and r = 3 so the answer is:

(x - 2) ^2 + (y - 1) ^2 = 3^2

= (x - 2) ^2 + (y - 1) ^2 = 9.