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13 January, 14:32

What is the slope of the line passing through (13,-2) and (3,-2)

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  1. 13 January, 16:24
    0
    Slope (m) = 0

    Slope (m) =

    ΔY

    ΔX

    = 0

    θ =

    arctan (ΔY)

    ΔX

    = 0°

    ΔX = 3 - 13 = - 10

    ΔY = - 2 - - 2 = 0

    Distance (d) = √ΔX2 + ΔY2 = √100 = 10
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