Members of a hospital advisory committee will be selected from 5 doctors and 4 nurses. The committee must have 2 doctors and 2 nurses.

How many possible combinations of doctors and nurses could be chosen for the committee?

16 possible ways

Step-by-step explanation:

Using the formular Cp, k = p!/I! (P-k) !

Where k = number of selected committee members

P = available number that can sit in the committee

For doctors, there are 5 doctors

C = 5!/2! (3) ! = 120/12 = 10ways

For nurses, there are 4

C = 4!/2! (2) ! = 24/4 = 6ways

Total possible ways=10 + 6 = 16 ways