Ask Question
25 January, 06:35

Fire load (MJ/m2) is the heat energy that could be released per square meter of floor area by combustion of contents and the structure itself. The following cumulative percentages are for fire loads in a sample of 388 rooms:

Fire load (MJ/m2) is the heat energy that could be

Value 0 150 300 450 600 750 900

Cumulative % 0 19.0 37.0 61.9 76.5 86.3 93.0

Value 1050 1200 1350 1500 1650 1800 1950

Cumulative % 95.0 97.8 98.1 99.5 99.6 99.8 100.0

(a) What proportion of fire loads are less than 600? At least 1200? (Round your answers to three decimal places.)

(b) What proportion of the loads are between 600 and 1200? (Round your answer to three decimal places.)

+2
Answers (1)
  1. 25 January, 08:31
    0
    a)

    The proportion of fire loads are less than 600 is 0.765

    The proportion of fire loads at least 1200 is 0.022

    b)

    The proportion of the loads between 600 and 1200 is 0.213

    Step-by-step explanation:

    The cumulative percent is given for various values of x.

    Value (x) Cumulative percent

    0 0

    150 0.19

    300 0.37

    450 0.619

    600 0.765

    750 0.863

    900 0.93

    1050 0.95

    1200 0.978

    1350 0.981

    1500 0.995

    1650 0.996

    1800 0.998

    1950 1

    a)

    The proportion of fire loads are less than 600

    P (x<600) = F (600) = 0.765

    Because we are given the cumulative percentages and the cumulative percentage for 450 will represent the proportion of fire loads that are less than 600.

    The proportion of fire loads at least 1200

    P (X≥1200) = 1-F (1200) = 1-0.978=0.022

    b)

    The proportion of the loads between 600 and 1200

    P (600≤X≤1200) = ?

    P (a≤X≤b) = F (b) - F (a)

    P (600≤X≤1200) = F (1200) - F (600) = 0.978-0.765=0.213
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Fire load (MJ/m2) is the heat energy that could be released per square meter of floor area by combustion of contents and the structure ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers