Ask Question
20 August, 08:29

You place a cup of 220 degrees F hot chocolate on a table in a room that is 72 degrees F, and 12 minutes later, it is 205 degrees F. Approximately how long will it be before the coffee is 175 degrees F? Round to the nearest minute. (Use newtons law of cooling: T (t) = Ta + (T0-Ta) e^-kt

+2
Answers (1)
  1. 20 August, 10:06
    0
    T (t) = 205 F

    T o = 220 F

    T a = 72 F

    t = 12 min;

    Here: k (constant) = ?

    205 = 72 + (220 - 72) * e ^ ( - 12 k)

    133 = 148 * e ^ (-12 k)

    e^ (-12k) = 0.89865

    - 12 k = ln 0.86865

    - 12 k = - 0.1068

    k = 0.0089

    Then we will plug in the formula:

    175 = 72 + (220 - 72) * e^ (-0.0089 t)

    103 = 148 * e^ (-0.0089 t)

    e^ (-0.0089 t) = 0.6959

    - 0.0089 t = ln 0.6959

    - 0.0089 t = - 0.36255

    t = 0.369255 : 0.0089

    t = 40.73 ≈ 41 min

    Answer: It will be 41 minutes later.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “You place a cup of 220 degrees F hot chocolate on a table in a room that is 72 degrees F, and 12 minutes later, it is 205 degrees F. ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers