Write the equation of a line that is parallel to y = 3x-2 and that passes through (9,-5).

y = - 1/3x + 2

Step-by-step explanation:

The slopes of perpendicular lines are negative reciprocals.

The line y = 3x - 2 has slope 3.

The perpendicular line has slope - 1/3.

Now we find the equation of the line that has slope - 1/3 and passes through (-9, 5).

y = mx + b

y = - 1/3x + b

5 = (-1/3) (-9) + b

5 = 3 + b

b = 2

The equation of the perpendicular is

y = - 1/3x + 2