The sum of four consecutive integers is 418. Find them.

Answer: 103, 104, 105, and 106

Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.

First represent your 4 consecutive integers as follows.

X ⇒ first integer

X + 1 ⇒ second integer

X + 2 ⇒ third integer

X + 3 ⇒ fourth integer

Since their sum is 418, our equation reads

x + (x + 1) + (x + 2) + (x + 3) = 418.

Simplifying on the left side we get 4x + 6 = 418.

Now we can subtract 6 from both sides of the equation and we have

4x = 412.

Now just divide both sides by 4 and we find that x = 103.

Finally, make sure you list all your answers.

If x is 103, then x + 1 is 104, x + 2 is 105, and x + 3 is 106

Therefore, our 3 consecutive integers are 103, 104, 105, and 106.