Ask Question
30 May, 03:57

The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If 2.51% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 2.12 m?

+1
Answers (1)
  1. 30 May, 06:47
    0
    F = 49,56 Kgs

    Step-by-step explanation:

    We Know that 113 calories = 4186 J

    Joules (energy unit in MKS system meter, kilograms, second)

    and 2,51 % of 4186 is 0,0251 * 4186 = 105.07 J

    That the energy available

    Work is W = F * d

    where F is the force you have to apply and d is traveled distance

    in this case F is the weight of the barbell

    Then

    F = W / d ⇒ F = 105.7 / 2.12 ⇒ F = 49,56 Kgs
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If 2.51% of ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers