Write the sum or difference in the standard form a + bi. (4 - 2i) + (9 + 6i)

13 - 4i

13 + 4i

-13 - 4i

-5 + 8i

Sum = 13 + 4i Difference = - 5 - 8i

Step-by-step explanation:

Given complex number as (4 - 2i) and (9 + 6i)

Sum of these complex number is

(4 - 2i) + (9 + 6i) = (4 + 9) + (6i - 2i)

= 13 + 4i

Difference of these complex number is

(4 - 2i) - (9 + 6i) = (4 - 9) - (2i + 6i)

= - 5 - 8i

Hence the sum and Difference of given complex numbers are

Sum = 13 + 4i Difference = - 5 - 8i Answer