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9 March, 09:41

Given that cosθ 1/3 and θ is acute, what is tanθ?

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  1. 9 March, 11:33
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    tanθ=2√2

    Step-by-step explanation:

    cosθ = 1/3, and θ is acute;

    cos²θ=1/9

    sin²θ+cos²θ=1

    sin²θ=1-cos²θ=1-1/9=8/9

    => sinθ=√ (8/9) = 2√2 / 3

    tanθ=sinθ/cosθ

    tanθ = (2√2 / 3) / (1/3) = 2√2

    tanθ=2√2
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