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19 April, 07:56

You are building a rectangular sandbox for a children's playground. The width of the sandbox is 4 times its height. The length of the sandbox is 8 ft more than 2 times its height. You have 40 ft3 of sand available to fill this sandbox. What are the dimensions of the sandbox?

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  1. 19 April, 09:41
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    In order to solve for the volume, we have to form a couple equations from the given:

    w = 4h - "The width of the sandbox is 4 times its height."

    l = 2h + 8 - "The length of the sandbox os 8 ft more than 2 times its height."

    w * l * h = 40 - "You have ft^3 of sand available to fill this sandbox"

    Alter the values of 'w' and 'l' in 'w * l * h = 40':

    (4h) * (2h + 8) * h = 40

    Multiply:

    (8h^2 + 32h) * h = 40

    8h^3 + 32h^2 = 40

    Divide all the numbers by eight:

    h^3 + 4h^2 = 5

    Factor the h^2 out:

    h^2 (h + 4) = 5

    h = 1 (This looks like the only possible number)

    We now know that h = 1.

    Recall the equations we formed at the start.

    w = 4 (1) = 4

    l = 2 (1) + 8 = 10

    The height is 1 foot, the width is 4 feet, and the length is 10 feet.
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