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29 January, 03:51

What is the length of a radius of the circle represented by the equation

x2 + y2 - 4x - 4y + 4 = 0?

A) 2 units

B) 4 units

C) 8 units

D) 16 units

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Answers (1)
  1. 29 January, 05:38
    0
    A) 2 units

    Step-by-step explanation:

    Given;

    x² + y² - 4x - 4y + 4 = 0

    Consider general circle equation;

    (x - h) ² + (y - k) ² = r²

    where;

    (h, k) is the center of the circle

    r is the radius of the circle

    x² + y² - 4x - 4y + 4 = 0

    subtract 4 from both sides of the equation

    x² + y² - 4x - 4y = - 4

    square half of coefficient of x and y, and add them to both sides of the equation

    x² + - 4x + (-2) ² + y² - 4y + (-2) ² = - 4 + (-2) ² + (-2) ²

    factorize x and y

    (x - 2) ² + (y - 2) ² = - 4 + 4 + 4

    (x - 2) ² + (y - 2) ² = 4

    (x - 2) ² + (y - 2) ² = 2²

    Compare this final equation to general equation of a circle

    (x - 2) ² + (y - 2) ² = 2²

    (x - h) ² + (y - k) ² = r²

    r = 2

    Thus, the length of a radius of the circle is 2 units
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