When Hiroto is writing, there is 0.92 probability that there will be no spelling mistakes on a page. One day, Hiroto writes an essay that is 11 pages long.

Assuming that Hiroto is equally likely to have a spelling mistake on each of the 11 pages, what is the probability that he will have a spelling mistake on at least one of the pages?

0.60

Step-by-step explanation:

Use binomial probability.

P = nCr pʳ qⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

The probability of a mistake on at least one page is 1 minus the probability of making no mistakes.

P (at least 1) = 1 - P (none)

P = 1 - ₁₁C₀ (0.08) ⁰ (0.92) ¹¹⁻⁰

P = 1 - (0.92) ¹¹

P = 0.60