Separate 846 into 3 parts so that the second part is twice the first part and the third part is triple the second part. Which of the following equations could be used to solve the problem?

Let us assume the first part to be = x

Then

The second part will be = 2x

The third part will be = 3 * 2x

= 6x

Then we can get to the equation

x + 2x + 6x = 846

9x = 846

x = 846/9

= 94

So

The first part will be = 94

The second part will be = 2x

= 2 * 94

= 188

The third part will be = 6x

= 6 * 94

= 564

So the three parts are 94, 188 and 564. The second option of 846 = x + 2x + 6x is the correct option.