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28 September, 01:45

Kay has 28 coins which includes nickels and dimes if the total is 2.35$, how many of each coin does Kay have?

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  1. 28 September, 04:26
    0
    19 dimes and 9 nickels

    Step-by-step explanation:

    Model the situation using two equations, then solve the system.

    let n be number of nickels and d be number of dimes.

    n + d = 28 < = This equation is about the number of coins.

    0.05n + 0.10d = 2.35 <=This equation is about the worth in dollars.

    Rearrange n + d = 28.

    n = 28 - d

    Now we can substitute this equation into the other one.

    Sub n = 28-d at the "d" variable for the equation 0.05n + 0.10d = 2.35

    0.05n + 0.10d = 2.35

    Now there is only one variable.

    0.05 (28 - d) + 0.10d = 2.35 <=distribute this

    0.05 (28 - d) + 0.10d = 2.35

    1.4 - 0.05d + 0.10d = 2.35 <=combine like terms

    1.4 + 0.05d = 2.35 < = begin to isolate d

    0.05d = 2.35 - 1.4

    0.05d = 0.95

    d = 0.95/0.05

    d = 19

    Now that we know d=19, we can substitute it into any equation.

    Choose the equation n + d = 28 because the numbers are easier.

    n + d = 28

    n + 19 = 28 <=isolate n

    n = 28 - 19

    n = 9

    Since n=9 and d=19, Kay has 9 nickels and 19 dimes.
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