When 2x^3-3x^2+kx-1 is divided by x-1 the remainder is 2 find k?

k = 4

Step-by-step explanation:

The remainder theorem tells you that the remainder from division of f (x) by (x-1) is f (1). Evaluating the expression for x=1 gives ...

2 (1³) - 3 (1²) + k (1) - 1 = 2 - 3 + k - 1 = k - 2

We want this to be equal to 2, so ...

k - 2 = 2

k = 4