Es

Find a polynomial equation that has double zeros at x = - 1, and x = 8.

y = (x + 1) (x - 8)

y = (x - 1) (x + 8)

9

y = (x + 1) 2 (x - 852

D)

y = (x - 1) 2 (x + 832

Submit

Question

Mathematics

Ethen Strickland

18 January, 11:26

Es

Find a polynomial equation that has double zeros at x = - 1, and x = 8.

y = (x + 1) (x - 8)

y = (x - 1) (x + 8)

9

y = (x + 1) 2 (x - 852

D)

y = (x - 1) 2 (x + 832

Submit

+4

Answers (1)

Know the Answer?

Anahi Monroe · Answer 1

f (x) = (x + 1) (x - 8)

Step-by-step explanation:

We have to find a polynomial equation that has double zeros at x = - 1 and at x = 8

Therefore, the polynomial has only two roots and it will be a quadratic polynomial and it has factors (x + 1) and (x - 8)

So, the polynomial is y = f (x) = (x + 1) (x - 8) (Answer)

EsFind a polynomial equation that has double zeros at x = - 1, and x = 8.y = (x + 1) (x - 8)y = (x - 1) (x + 8)9y = (x + 1) 2 (x - 852D)y = (x - 1) 2 (x + 832Submit

Es

Find a polynomial equation that has double zeros at x = - 1, and x = 8.

y = (x + 1) (x - 8)

y = (x - 1) (x + 8)

9

y = (x + 1) 2 (x - 852

D)

y = (x - 1) 2 (x + 832

Submit