A ball was thrown upward into the air. The height, in feet, of the ball above the ground t seconds after being thrown can be determined by the expression - 16t^2+40t+3. What is the meaning of the 3 in the expression?

C.) The ball was thrown from a height of 3 feet

Step-by-step explanation:

In the standard form of a quadratic function, f (x) = ax² + bx + c,

c is the constant term (also known as the y-intercept of the parabola)

In this situation, the ball is thrown up into the air and the flight path will be in the shape of a parabola

The equation y = - 16t² + 40t + 3 has a y-intercept of 3, meaning the flight path began at 3 feet above the ground, as you can imagine by looking at the graph of the equation, below. The y-intercept is at (0,3)