The perimeter of a basketball court is 284 ft. the length is 40 ft longer than the width. find the dimensions of the court.

We know that the perimeter is the distance around an object. This is also 2 times the length + 2 times the width. We know the width would be X and the length would be 40 feet longer so it is x+40. Now we have 2 (X) + 2 (x+40) = 284

Doing the distributive property you would get 2x + 2x + 80=284

add like terms to get 4x+80=284

subtract 80 from both sides to get 4x=204

divide both sides by 4 to get x=51

Width is 51 and width is 40 more than that so length is 91

284=2x+2 (x+40)

284=4x+80

204=4x

51=x

dimensions 51 ft by 91ft