Ask Question
15 August, 00:03

In the xy-coordinate plane, the graph of the equation y=2x^2-12x-32 has zeros at x=d and x=e, where d>e. The graph has a minimum at (f,-50) what are the vaules of d, e, and f?

+4
Answers (1)
  1. 15 August, 03:54
    0
    To find the zeroes solve fro x:-

    2 (x^2 - 6x - 16) = 0

    2 (x - 8) (x + 2) = 0

    x = {8, - 2

    so d = 8 and e = - 2

    the x coordinate of the minimum value = - b / 2a = 12 / 2*2 = 3

    f = 3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “In the xy-coordinate plane, the graph of the equation y=2x^2-12x-32 has zeros at x=d and x=e, where d>e. The graph has a minimum at (f,-50) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers