The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

A:No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64

B: No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

C:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64

D:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

@taskmasters or anybody

Question

Mathematics

Abraham

5 July, 22:06

The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units?

A:No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64

B: No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

C:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64

D:Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32

@taskmasters or anybody

+2

Answers (1)

Know the Answer?

Case Strong · Answer 1

B. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32

Perimeter = 2 (l + w)

Perimeter = 64

Assuming: P = 64; w = 11; l = ?

64 = 2 (l + 11)

64/2 = l + 11

32 - 11 = l

length = 21.