What is the simplified form of i ^32?

A. - i

B. 1

C. i

D. - 1

1

Step-by-step explanation:

The pattern of imaginary numbers taken to exponents goes as thus:

i^1 = i

i^2 = - 1

i^3 = - i

i^4 = 1

To solve this problem, divide the exponent by 4:

32/4 = 8

Now rewrite i^32 as (i^4) ^8

(When exponents are raised by an exponent you multiply them together)

i^4=1, this is your answer

divide exponent by 4

since the remainder is zero, the equation can be rewritten as i^0 and any number to the 0 power is 1