Write an equation of a line that is through (6,-3) and is perpendicular to 3x+y=6

Answer: y=-1/3x-1

Step-by-step explanation:

1) Isolate y by subtracting 3x from both sides.

3x+y=6 - > y=3x+6

2) Find the negative inverse of 3 - which is - 1/3.

3) Use y=mx+b and plug in what you know.

-3=-1/3 (6) + b

4) Solve for b.

-3=-2+b

-1=b

5) Put it all together in y=mx+b format.

y=-1/3x-1