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3 December, 07:05

A bag contains 4 white, 2 blue, and 6 red marbles. A marble is drawn from the bag, replaced, and another marble is drawn. Find the following

probabilities:

Enter your answers a simplified fractions, with / representing the fraction bar

1. both marbles are red

2. both marbles are blue

3. the first marble is red and the second is blue

other is red

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Answers (1)
  1. 3 December, 10:03
    0
    Step-by-step explanation:

    Total marble = 6+4+2 = 12

    n (W) = 4

    n (B) = 2

    n (R) = 6

    P (W) = 4/12 = 1/3

    P (B) = 2/12 = 1/6

    P (R) = 6/12 = 1/2

    1. P (R and R) = 1/2 * 1/2 = 1/4

    2. P (B and B) = 1/6 * 1/6 = 1/36

    3. P (R and (B or R) = 1/6 * (1/6+1/2)

    = 1/6 * (2/3)

    = 1/9
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