There are 46 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of 5 min and a standard deviation of 4 min. (Round your answers to four decimal places.) (a) If grading times are independent and the instructor begins grading at 6:50 P. M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P. M. TV news begins? (b) If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

Question

Mathematics

Bridgett

21 April, 23:22

There are 46 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of 5 min and a standard deviation of 4 min. (Round your answers to four decimal places.) (a) If grading times are independent and the instructor begins grading at 6:50 P. M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P. M. TV news begins? (b) If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

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Answers (1)

Know the Answer?

Jimmy Ho · Answer 1

a) P (T < 250 mins) = 0.7695

b) P (T > 260 mins) = 0.1344

Step-by-step explanation:

- The RV from a sample has the following parameters that are mean = 5 mins, and standard deviation s = 4 mins.

- The entire population has n = 46 students.

- We will first compute the population mean u and population standard deviation σ as follows:

u = n*mean

u = 46*5 = 230 mins

σ = sqt (n) * s

σ = sqt (46) * 4

σ = 27.129 mins

- Approximating that the time taken T to grade the population of entire class follows a normal distribution with parameters u and σ as follows:

T~ N (230, 27.129)

Find:

- If grading times are independent and the instructor begins grading at 6:50 P. M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P. M. TV news begins?

- The total time till 6:50 PM to 11:00 PM is (4 hr and 10 mins) = 250 mins.

- We will compute the Z-value as follows:

Z = (250 - 230) / 27.129

Z = 0.7372

- Then use the Z-Tables and determine the probability:

P (T < 250 mins) = P (Z < 0.7372)

P (T < 250 mins) = 0.7695

Find:

- If the sports report begins at 11:10, what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

- For the teacher to miss the sports report he must take more time than 6:50 PM to 11:10 P. M.

- The total time till 6:50 PM to 11:10 PM is (4 hr and 20 mins) = 260 mins.

- We will compute the Z-value as follows:

Z = (260 - 230) / 27.129

Z = 1.10582

- Then use the Z-Tables and determine the probability:

P (T > 260 mins) = P (Z > 1.10582)

P (T > 260 mins) = 0.1344