The LCM of two prime numbers x and y (x>y) is 161. Find the remainder when x is divided by y.

Answer

2

Step-by-step explanation:

Since LCM of x and y is 161, this means x and y are factors of 161. The factors of 161 are:

1, 7, 23, 161

Since x and y are prime numbers and it is given that x > y, the only possible solution for x and y is:

x = 23

y = 7

We have to find what is the remainder when x=23 is divided by y=7. We know that 7 times 3 = 21. This means, when 23 is divided by 7, the quotient is 3 and the remainder is 2.

Therefore, the answer to this question is 2.