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Luka Waller
14 May, 04:46
What are the solutions to 2x^2+7x=4?
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Mohammad Brooks
14 May, 06:45
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2x^2+7x-4=0
2x^2+8x-x-4=0
2x (x+4) - 1 (x+4) = 0
(2x-1) (x+4) = 0
So the zeros or solutions occur when x=-4 and 1/2
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