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26 August, 09:14

Given fx) = 17 - x2, what is the average rate of change in f (x) over the interval [1, 5]?

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Answers (2)
  1. 26 August, 11:03
    0
    Answer: A. - 6
  2. 26 August, 12:49
    0
    Let [a, b] = the interval

    The average rate of change can be found by using [f (b) - f (a) ] / (b - a).

    Let a = 1 and b = 5.

    Let R = rate of change

    17 - x^2

    R = [17 - 5^2] - [17 - 1^2] / (5 - 1)

    R = [17 - 25] - [17 - 1]/4

    R = [ (-8) - (16) ]/4

    R = (-24) / 4

    R = - 6

    Done.
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