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10 August, 20:07

A retired woman has $90,000 to invest but needs to make $3,000 a year from the interest to meet certain living expenses. One bond investment pays 15% annual interest. The rest of it she wants to put in a CD that pays 7%. If we let x be the amount the woman invests in the 15% bond, how much in dollars will she be able to invest in the CD?

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  1. 10 August, 22:36
    0
    see below

    Step-by-step explanation:

    $3000 is not a right number or $90000

    Assume n instead of $3000, then

    x*0.15 + (90000-x) * 0.07 = n

    is required equation

    0.15x+6300-0.07x=n 0.08x+6300=n 0.08x = n-6300

    x = (n-6300) / 0.08 is the amount invested in the 15% bond

    Consider n> $6300

    Then 90000 - x will be the amount invested in the CD
  2. 10 August, 23:02
    0
    Answer: any amount from 0 to 90000 USD

    Step-by-step explanation:

    x USD will be paid for 15% bonds that makes x*0.15 USD / per year

    So 90000-x will be paid for 7% bonds, that makes (90000-x) * 0.07 USD/per year = 6300-0.07x USD / per year.

    So the total amount the woman gets from both investments yearly should be not less than 3000 USD/per year

    Otherwise

    0.15*x+6300-0.07*x>=3000

    0.08*x+6300>=3000

    The inequation is correct for any x>=0

    The woman will be able invest in CD any amount from 0 to 90000 USD.

    If we suppose that investments in CD more safe we'd recommend to the lady to invest all money to CD.
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