The length of rectangle is eight more than twice its width. The perimeter is 96 ft. What are the dimensions

Because we don't know what the width of the rectangle we make it equal to x. So to find the length you would make it 2x+8 becuase if the length is 8 more then the width you add 8 to x, x+8. And becuase the length it "twice" the with you would make it 2x+8. Now you make everything = to 96

2x+8 + 2x+8 + x + x = 96 (you put each equation in twice becuase you have 2 width and length on a rectangle)

6x + 16 = 96

6x=80

X=13.3334

Now you plug in 13 in for x

2 (13.333) + 8=34.666 (length = 34.667)

34.666+34.666+13.333+13.333=96

(Nicer numbers if you round)

35+35+13+13=96

L=35

W=13

L = length

W = width

L = 2 (2W + 8)

W = 2W

Perimeter: 96 = 4W + 16 + 2W

96 = 6W + 16

80 = 6W

13.33 = W

Plug this into the equation:

2 (13.33) + 8

26.67 + 8 or 34.67 = L