The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of the rectangle. Round off your answers to the nearest hundredth.

dimensions are 2.19 inches by 9.14 inches

Step-by-step explanation:

Here, we are interested in knowing the dimensions of the rectangle

Now, let the width of the rectangle be x, from the question, we can write;

6x-4 as the length

Area of rectangle = l * b

x (6x-4) = 20

6x^2 - 4x = 20

divide through by 2

3x^2-2x = 10

3x^2 - 2x - 10 = 0

using quadratic formula;

x = - b ± √ (b^2 - 4ac) / 2a

From the quadratic equation, a = 3, b = - 2 and c = - 10

substituting these values, we have

x = 2 ± √ (-2) ^2 - 4 (3) (-10)) / 6

x = 2 ± √ (124) / 6

x = 2 + √ (124) / 6 or 2 - √ (124) / 6

x = (2+11.14) / 6 or (2-11.14) / 6

x = 2.19 or - 1.52

Since width cannot be negative, we choose 2.19 alone

So the length is 6 (2.19) - 4 = 9.14