A stone is thrown straight up from the edge of a roof, 775 feet above the ground, at a speed of 16 feet per second. A. Remembering that the acceleration due to gravity is - 32ft/sec2, how high is the stone 4 seconds later?

435 ft off the ground

Step-by-step explanation:

Use

s = u t + 1/2 at²

Here

s = distance traveled

u = initial velocity

t = time

a = acceleration

putting values in equation

= 16 * 4 + 1/2 32 * 16

= 64 + 256

= 320

So the stone is

775 - 320 = 435 ft off the ground