Which equation has the solutions x = 5 ± 2 square root 7 all over 3

1. 3x2 - 5x + 7 = 0

2. 3x2 - 5x - 1 = 0

3. 3x2 - 10x + 6 = 0

4. 3x2 - 10x - 1 = 0

4. 3x^2 - 10x - 1 = 0

Step-by-step explanation:

You can write the quadratic from the roots:

0 = (x - (5-2√7) / 3) (x - (5+2√7) / 3)

= (x - 5/3) ^2 - (2√7/3) ^2

= x^2 - 10/3x + 25/9 - 28/9

= x^2 - 10/3x - 1/3

Multiplying by 3 gives ...

0 = 3x^2 - 10x - 1