A consumer organization estimates that 32% of the households in a particular community have one television set, 38% have two sets, and 16% have three or more sets. If two households are chosen at random, what is the probability that at least one has one or more television sets

Question

Mathematics

Maximo Kaiser

7 August, 13:06

A consumer organization estimates that 32% of the households in a particular community have one television set, 38% have two sets, and 16% have three or more sets. If two households are chosen at random, what is the probability that at least one has one or more television sets

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Kadyn Daniels · Answer 1

If two households are chosen at random, the probability that at least one has one or more television sets is equal to 0.9804 or (98.04%)

Step-by-step explanation:

32% of the households have one television set, 38% have two sets 16% have three or more sets

Then 100% - (32% + 38% + 16%) = 14% of households does not have any television set

the probability that both of the two randomly chosen households does not have any television set is 0.14*0.14 = 0.0196

If two households are chosen at random, the probability that at least one has one or more television sets is equal to

1 - (the probability that both of the two randomly chosen households does not have any television set) = 1 - 0.0196 = 0.9804 (98.04%)