Ask Question
30 November, 15:05

Suppose that a fair, 6 sided die is rolled. Let X indicate the event that an even number is rolled (in other words, X = 1 if an even number is rolled and X = 0 otherwise). Let Y indicate the event that 2, 3, or 4 is rolled (in other words, Y = 1 if 2, 3, or 4 is rolled and Y = 0 otherwise). Find P (X = 0, Y = 1).

+1
Answers (1)
  1. 30 November, 17:05
    0
    Answer: 1/2, 1/2

    Step-by-step explanation:

    A die has 6 faces.

    Total number of faces = 6

    Possible outcomes are : 1,2,3,4,5,6

    Even numbers : 2, 4, and 6 = 3

    Non even numbers: 1,3, and 5 = 3

    First statement:

    P (Even number) = 3 / 6 = 1/2

    P (X=1) = 1/2

    P (odd number) = 3/6 = 1/2

    P (X=0) = 1/2

    Second statement:

    P (2) = 1/6

    P (3) = 1/6

    P (4) = 1/6

    P (2 or 3 or 4) = (1/6) + (1/6) + (1/6)

    P (2 or 3 or 4) = (1+1+1) / 6 = 3/6 = 1/2

    Thus,

    P (Y=1) = 1/2

    Therefore,

    P (X = 0, Y=1) = 1/2, 1/2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose that a fair, 6 sided die is rolled. Let X indicate the event that an even number is rolled (in other words, X = 1 if an even number ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers