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27 May, 23:01

your family goes to a restaurant for dinner. there are 6 people in your family. some order the chicken dinner for $14.80 and some order the steak for $17. if the total bill was $91, how many people ordered chicken and how many ordered steak?

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Answers (2)
  1. 28 May, 00:37
    0
    (14.80) (5) = 74

    6-5 = 1

    (17) (1) = 17

    74 + 17 = 91

    5 family members orders chicken, and only one orders steak.
  2. 28 May, 01:41
    0
    5 ordered chicken, and 1 ordered steak

    Step-by-step explanation:

    let's make c the number that ordered the chicken, and s the number that ordered steak. we're going to make an equation to solve for it:

    14.8 c + 17 s = 91

    We are in a situation where if someone orders chicken, they cannot have also ordered steak, and vice versa. This means we can make c or s equal to (6 - s) or (6 - c) respectively.

    I will choose to replace s with (6 - c)

    14.8c + 17 (6 - c) = 91

    simplify

    14.8c - 17 c + 102 = 91

    subtract 102 from both sides and simplify cs

    -2.2c = - 11

    divide by - 2.2

    c = 5

    This means that 5 people ordered chicken, and 1 ordered steak, bringing the total to 14.8 * 5 + 17 * 1 = 74 + 17 = 91

    If you do the math the other way (replacing c with (6-s), you get the same answers (c = 5, s = 1)
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