Two square plots of land contains 74square feet. If the side of one plot is 2 feet longer than the side of other plot, find the dimension of both plots

The area of other plot = s² = 5² = 25 sq feet

The area of one plot = (5 + 2) ² = 7² = 49 sq feet

Step-by-step explanation:

Given as:

The total area of two square plots = 74 sq feet

Let The side of other plot = s feet

So, The side of one plot = (s + 2) feet

Now,

∵ Area of square = side²

Area of other plot = s²

Area of one plot = (s + 2) ²

As, The total area of two square plots = 74 sq feet

So, s² + (s + 2) ² = 74 sq feet

Or, s² + s² + 4s + 4 = 74

Or, 2s² + 4s - 70 = 0

Or, s² + 2s - 35 = 0

Or, s² - 5s + 7s - 35 = 0

Or, s (s - 5) + 7 (s - 5) = 0

So, (s - 5) (s + 7) = 0

∴ s = 5, - 7

Thus The area of other plot = s² = 5² = 25 sq feet

And The area of one plot = (5 + 2) ² = 7² = 49 sq feet Answer