A spinner has equally sized sections, of which are gray and of which are blue. The spinner is spun twice. What is the probability that the first spin lands on gray and the second spin lands on blue?

Let's Take 8 sections and in which 6 are grey and 2 are blue.

The probability that the first spin lands on blue = 2/8 = ¼

The probability that the second spin lands on gray = 6/8 = ¾

The probability that the first spin lands on blue and the second spin lands on gray is

(¼) (¾) = 3/16

These events are independent, so you can just multiply the probabilities

25%

Step-by-step explanation:

50% chance for spin one to be gray and 50% chance for spin two to be blue. Put them together for that order and you get 25%.